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19.05.2023the following question

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## Step-by-step answer

19.05.2023, solved by verified expert

Force of earth gravity on 1 kg mass is 9.8 N.

Since the mass is at earth surface, therefore its distance from the centre of earth is equal to the radius of the earth i.e. 6400 km.

The force of earth gravity is calculated as

F=GMm/r^2 =(6.67*〖10〗^(-11)*6*〖10〗^24*1)/〖(64*〖10〗^6)〗^2 =9.8 N

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Physics

Calculate the force of earth s gravity on a 1kg mass at earth s surface. the mass of the earth is 6.0

Step-by-step answer

**P** Answered by PhD 1

Force of earth gravity on 1 kg mass is 9.8 N.

Since the mass is at earth surface, therefore its distance from the centre of earth is equal to the radius of the earth i.e. 6400 km.

The force of earth gravity is calculated as

F=GMm/r^2 =(6.67*〖10〗^(-11)*6*〖10〗^24*1)/〖(64*〖10〗^6)〗^2 =9.8 N

Chemistry

What is the force of gravity between the earth and the mass of 1kg placed on its surface? (Mass of earth = 6 x 10^24 kg)

Step-by-step answer

**P** Answered by PhD

Given that,

Mass, m = 1 kg

Mass of the Earth,

Radius of Earth, r = 6378 km

To find,

The gravitational force.

Solution,

The formula for the gravitational force is given by :

So, the required force is 9.83 N.

Physics

a screw has a head diameter of 0.812 m and a thread width of 0.318 cm. What is the ideal mechanical advantage?

Step-by-step answer

**P** Answered by PhD 1

The question specifies the diameter of the screw, therefore the IMA of this screw is 0.812? / 0.318 = 8.02

Physics

A puck moves 2.35 m/s in a -22.0° direction. A hockey stick pushes it for 0.215 s, changing its velocity to 6.42 m/s in a 50.0° direction. What was the magnitude of the acceleration?

Step-by-step answer

**P** Answered by PhD

Answer:

7.25 secs.

Explanation:

First find the distance it takes to stop

s = [v^2-u^2]/2a = 0^2 - 8.7^2/2[-2.4] = 8.7^2/4.8

Next find the time it takes to go that distance , s = ut +[1/2] at^2

8.7^2/4.8 = 8.7t +[1/2] [ -2.4]t^2 , rearrange and

t^2 -[8.7/1.2]+ 8.7^2/[(1.2)(4.8)]=0 complete the square

[t - (8.7/2.4)]^2=0

t = 8.7/2.4 = 3.625 secs

At this stage the deceleration will push the object back in the direction it came from for another 3.625 secs when it will be 8.7 m/s again

Total time , T =2t = 7.25 secs.

Note:

The term differential is used in calculus to refer to an infinitesimal (infinitely small) change in some varying quantity. For example, if x is a variable, then a change in the value of x is often denoted Δx (pronounced delta x). The differential dx represents an infinitely small change in the variable x.

Physics

compare the momentum of a 6,300 kg elephant walking 0.11 m/s and a 50-kg dolphins swimming 10.m/s

Step-by-step answer

**P** Answered by PhD 1

First sum applied the Newton's second law motion: F = ma

Force = mass* acceleration

This motion define force as the product of mass times Acceleration (vs.Velocity). Since acceleration is the change in velocity divided by time,

force=(mass*velocity)/time

such that, (mass*velocity)/time=momentum/time

Therefore we get mass*velocity=momentum

Momentum=mass*velocity

Elephant mass=6300 kg; velocity=0.11 m/s

Momentum=6300*0.11

P=693 kg (m/s)

Dolphin mass=50 kg; velocity=10.4 m/s

Momentum=50*10.4

P=520 kg (m/s)

The elephant has more momentum(P) because it is large.

Physics

An electrical kettle supplies 20,000j of energy to heat 0.5kg of water. What is the temperature change? The specific heat capacity of water is 4200j/kg.

Step-by-step answer

**P** Answered by PhD

The change in temperature is 9.52°CExplanation:Since, the heat supplied by the electric kettle is totally used to increase the temperature of the water.Thus, from the law of conservation of energy can be stated as:Heat Supplied by Electric Kettle = Heat Absorbed by WaterHeat Supplied by Electric Kettle = m C ΔTwhere,Heat Supplied by Electric Kettle = 20,000 JMass of water = m = 0.5 kgSpecific Heat Capacity of Water = C = 4200 J/kg.°CChange in Temperature of Water = ΔTTherefore,20,000 J = (0.5 kg)(4200 J/kg.°C) ΔTΔT = 20,000 J/(2100 J/°C)ΔT = 9.52°C

Physics

Jordan lifts a 100-kilogram barbell from the floor to a height of 2.0 meters in 1.5 seconds. The amount of power he generates is about ____ watts.

Step-by-step answer

**P** Answered by PhD 1

Weight of barbell (m) = 100 kg

Uplifted to height (h) = 2m

Time taken= 1.5 s

Work done by Jordan = potential energy stored in barbell = mgh

= 100×2×9.8

= 1960J

Power = energy/time

= 1960/1.5

1306.67watts

Physics

Jasmine, who weighs 400 newtons, moves up a 5.0-meter climbing wall in 15 seconds. The amount of power generated by Jasmine as she climbs the wall is about ____ watts.

Step-by-step answer

**P** Answered by PhD

Weight of jasmine (m) = 400 N

Height climbed on wall (h) = 5m

Total time taken in climbing = 5 sec

Work done in climbing the wall = rise in potential energy = mgh

= 400×9.8×51

= 19600J

Power generated by Jasmine = potential energy / time

= 19600/5

= 3920Watts

Physics

Klay Thompson and Draymond Green wanted to play a joke on Steph Curry. Klay threw a ballon horizontally at 50 m/s from 150 m high bridge. How far did the ballow go when it landed?

Step-by-step answer

**P** Answered by PhD

The horizontal and vertical motions of balloons are independent from each other.

Let vertical component of initial velocity U' horizontal component of initial velocity U"

Time of landing (t) is found with the help of vertical motion.

Since vertical component of initial velocity of balloon is zero(U' = 0)

From equation h = U't + 1/2gt^2

h = 1/2gt^2

t = √(2h/g)

t = √( 2×150/9.8)

t = 5.53 sec

Horizontal velocity = 50m/s

Horizontal range of balloon, R = U"t

= 50× 5.53

= 27.65m

So the balloon will go 27.65 metre away from the bridge

Physics

an object falls from a high building . ignoring air resistance what will it’s velocity be after 3 seconds of falling ?

Step-by-step answer

**P** Answered by PhD 1

Gravity acceleration (g) = 9.8m/s^2

Time (t) = 3sec

Acceleration = velocity/time

Velocity = acceleration×time

= 9.8×3

= 29.4m/s

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